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Print all words in a file sorted by length

Terminal - Print all words in a file sorted by length
for a in $(< FILENAME); do echo "$(bc <<< $(wc -m<<<$a)-1) $a";done|sort -n
2012-04-02 02:15:52
User: codecaine
Functions: echo sort
0
Print all words in a file sorted by length

Alternatives

There are 4 alternatives - vote for the best!

Terminal - Alternatives
for a in $(cat sample.txt); do echo "$(wc -m<<<$a) $a";done|sort -n
2012-03-15 08:51:42
User: knoppix5
Functions: cat echo sort
0

optionally you can add

|cut -d' ' -f2|uniq

to the end of the command line.

for a in $(cat sample.txt); do echo "${#a} $a";done|sort -n
for w in $(tr 'A-Z ,."()?!;:' 'a-z\n' < sample.txt); do echo ${#w} $w; done | sort -u | sort -n
2012-03-15 14:14:11
User: flatcap
Functions: echo sort tr
Tags: bash sort tr
0

Take a file and ,."()?!;: give a list of all the words in order of increasing length.

First of all use tr to map all alphabetic characters to lower case and also strip out any puntuation.

A-Z become a-z

,."()?!;: all become \n (newline)

I've ignored - (hyphen) and ' (apostrophe) because they occur in words.

Next use bash to print the length ${#w} and the word

Finally sort the list numerically (sort -n) and remove any duplicates (sort -u).

Note: sort -nu performs strangely on this list. It outputs one word per length.

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