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May 19, 2015 - A Look At The New Commandlinefu
I've put together a short writeup on what kind of newness you can expect from the next iteration of clfu. Check it out here.
March 2, 2015 - New Management
I'm Jon, I'll be maintaining and improving clfu. Thanks to David for building such a great resource!

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Print out "string" between "match1" and "match2"

Terminal - Print out "string" between "match1" and "match2"
echo "string" | sed -e 's/.*match1//' -e 's/match2.*$//'
2009-04-01 15:01:27
User: P17
Functions: echo sed
Print out "string" between "match1" and "match2"

But who knows to delete the rest of the lines?

I want only "string".


There are 7 alternatives - vote for the best!

Terminal - Alternatives

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What others think

Not entirely sure what you're wanting, this maybe?

sed -e 's/^.*\(string\).*$/\1/'
Comment by TheMightyBuzzard 472 weeks and 6 days ago

This should be what you're looking for. Only prints lines with match1 and match2 in them, and only the section between the two matches.

sed -ne 's/.*\(match1.*match2\).*/\1/p'

or, a bit easier:

egrep -o 'match1.*match2'

Works with standard grep here, too, but YMMV.

Comment by Viaken 472 weeks and 6 days ago

If you don't know what you're after, why are you posting to CLF? This isn't a support forum, but a repository of the best commands on the web. BTW:

echo "string" | awk '/match1/,/match2/'
Comment by atoponce 472 weeks and 5 days ago

I got it:

sed -n '/match1/,/match2/p' file.txt | sed -e '/match1/d' | sed -e '/match2/d'
Comment by P17 470 weeks ago

Your point of view

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