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Replaces A with B in binary file "orig" and saves the result to "new". You must have the hex representations of A & B. Try od: echo -e "A\c" | od -An -x
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By default xxd creates a formatted hex dump, which will cause this command to miss instances where the string wraps to a new line. Use the -p option instead to skip formatting:
xxd -p < orig | sed 's/HEXA/HEXB/' | xxd -r -p > new $This has a few problems still. Inefficient for large files, doesn't align on byte boundries and xxd -p still has new-lines so wrapped hex won't get matched. You can use Perl's RE to do hex matches for you by using the \x{XX} expression where "XX" is the hex byte code. For example:
perl -pe 's/\x{3C}\x{21}/\x{3D}/g;s/\x{2D}/\x{3D}/g' < orig > newThis replaces "
Oops, the end of my comment got truncated. Anyways, you can look up 0x3C,0x21, etc. to see what chars I'm replacing and with what in my example above.