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change the all files which contains xxxxx to yyyyyy

Terminal - change the all files which contains xxxxx to yyyyyy
grep -r -l xxxxx . | xargs perl -i -pe "s/xxxxx/yyyyy/g"
2009-02-06 08:18:50
User: hassylin
Functions: grep perl xargs
change the all files which contains xxxxx to yyyyyy

This script first find all files which contains word xxxxx recursively. Then replace the word xxxxx to yyyyy of the files.

Use case:

- Web site domain change

- Function name change of the program


There is 1 alternative - vote for the best!

Terminal - Alternatives

Know a better way?

If you can do better, submit your command here.

What others think

The perl command is wrong, shoud be perl -i -pe "s/xxxx/yyyy/g"

Also, this breaks on files with spaces.

echo "This contains xxxxx, see?" > "filename" echo "This also contains xxxxx, see?" > "filename two" cat "filename"

This contains xxxxx, see?

cat "filename two"

This also contains xxxxx, see?

grep -r -l xxxxx . | xargs perl -pi "s/xxxxx/yyyyy/g"

Can't open perl script "s/xxxxx/yyyyy/g": No such file or directory

grep -r -l xxxxx . | xargs perl -i -pe "s/xxxxx/yyyyy/g"

Can't open two: No such file or directory, line 1.

cat "filename"

This contains yyyyy, see?

cat "filename two"

This also contains xxxxx, see?

This works better:

grep -r -l xxxxx . | while read f ; do perl -i -pe 's/xxxxx/yyyyy/g' "$f" ; done cat "filename two"

This also contains yyyyy, see?

Comment by zjuul 320 weeks ago

Thanks. I fixed the typo.

Comment by hassylin 320 weeks ago

Here's a find/sed equivalent:

find . -exec sed -ir 's/xxxxx/yyyyy/g' {} \;
Comment by porges 320 weeks ago

Your point of view

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