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Remove current directory

Terminal - Remove current directory
removedir () { echo "Deleting the current directory $PWD Are you sure?"; read human; if [[ "$human" = "yes" ]]; then blah=$(echo "$PWD" | sed 's/ /\\ /g'); foo=$(basename "$blah"); rm -Rf ../$foo/ && cd ..; else echo "I'm watching you" | pv -qL 10; fi; }
2010-01-17 11:34:38
User: oshazard
Functions: basename cd echo read rm sed
-3
Remove current directory

CHANGELOG

Version 1.1

removedir () { echo "You are about to delete the current directory $PWD Are you sure?"; read human; if [[ "$human" = "yes" ]]; then blah=$(echo "$PWD" | sed 's/ /\\ /g'); foo=$(basename "$blah"); rm -Rf ../$foo/ && cd ..; else echo "I'm watching you" | pv -qL 10; fi; }

BUG FIX:

Folders with spaces

Version 1.0

removedir () { echo "You are about to delete the current directory $PWD Are you sure?"; read human; if [[ "$human" = "yes" ]]; then blah=`basename $PWD`; rm -Rf ../$blah/ && cd ..; else echo "I'm watching you" | pv -qL 10; fi; }

BUG FIX:

Hidden directories (.dotdirectory)

Version 0.9

rmdir () { echo "You are about to delete the current directory $PWD. Are you sure?"; read human; if [[ "$human" = "yes" ]]; then blah=`basename $PWD`; rm -Rf ../$blah/ && cd ..; else echo "I'm watching you" | pv -qL 10; fi; }

Removes current directory with recursive and force flags plus basic human check. When prompted type yes

1. [user@host ~]$ ls

foo bar

2. [user@host ~]$ cd foo

3. [user@host foo]$ removedir

4. yes

5. rm -Rf foo/

6. [user@host ~]$

7. [user@host ~]$ ls

bar

Alternatives

There are 2 alternatives - vote for the best!

Terminal - Alternatives

Know a better way?

If you can do better, submit your command here.

What others think

If you're doing something like this: "rm -Rf ../$blah/", you have to make sure that $blah is set, or at least give it a default value like ${blah:-DEFAULTVALUE} and quote it. You need to quote $PWD also. Imagine that $PWD is unset or has a space in it in this scenario. "basename $PWD" fails and $blah remains unset. The next command becomes "rm -Rf ..//", which could be disasterous if you're one level up from the root directory.

Comment by eightmillion 289 weeks and 2 days ago

Thank you eightmillion.

Can you find any problems with this revision?

removedir () { echo "You are about to delete the current directory $PWD Are you sure?"; read human; if [[ "$human" = "yes" ]]; then blah=$(echo "$PWD" | sed 's/ /\\ /g'); foo=$(basename "$blah"); rm -Rf ../$foo/ && cd ..; else echo "I'm watching you" | pv -qL 10; fi; }
Comment by oshazard 289 weeks and 2 days ago

That is a bit better, although you don't need to mess with the sed business and you still need to quote your variable when you call "rm -Rf" or you could end up deleting multiple unintended directories. This is pretty workable:

removedir(){ read -p "You are about to delete the current directory $PWD Are you sure? " human;if [ "$human" = "yes" ]; then foo=$(basename "$PWD");[ -z "$foo" ] && { echo "Error: Couldn't get working directory" >&2;return 1;}; rm -Rf ../"$foo"/ && cd ..; else echo "I'm watching you" | pv -qL 10; fi; }

Notice the "[ -z $foo ]" part. That checks if the variable $foo is null. If it is null, then the function echoes an error message to stderr and returns a non-zero exit status. Otherwise, it continues. Also notice "read -p". You can specify a prompt for the read command. On a side note, a neat way to get the basename of the current working directory in Bash is to use "${PWD##*/}".

Comment by eightmillion 289 weeks and 1 day ago

Your point of view

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