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May 19, 2015 - A Look At The New Commandlinefu
I've put together a short writeup on what kind of newness you can expect from the next iteration of clfu. Check it out here.
March 2, 2015 - New Management
I'm Jon, I'll be maintaining and improving clfu. Thanks to David for building such a great resource!

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Psst. Open beta.

Wow, didn't really expect you to read this far down. The latest iteration of the site is in open beta. It's a gentle open beta-- not in prime-time just yet. It's being hosted over at UpGuard (link) and you are more than welcome to give it a shot. Couple things:

  • » The open beta is running a copy of the database that will not carry over to the final version. Don't post anything you don't mind losing.
  • » If you wish to use your user account, you will probably need to reset your password.
Your feedback is appreciated via the form on the beta page. Thanks! -Jon & CLFU Team

print line and execute it in BASH

Terminal - print line and execute it in BASH
echo <command>; !#:0-$
2010-12-15 08:28:50
User: infinull
Functions: echo
print line and execute it in BASH

!# is the currennt line so far, by using !#:- you can go from the second arg (it's zero indexed) to the last ($)

(did I understand the problem correctly?)


There are 5 alternatives - vote for the best!

Terminal - Alternatives
bash -x script.sh
2010-12-15 17:01:51
Functions: bash

If script.sh contains only these two lines:

$ uname -a

$ whoami

set -x
$ echo "command"; `!#:0-$
2011-04-28 17:09:25
Functions: echo

since we're repeating the command there after the semicolon, we only need one backtick

2010-12-15 07:48:25
User: chaliyans

Is there a way to print the line BASH is executing without copy+paste the line inside an 'echo' command?

Know a better way?

If you can do better, submit your command here.

What others think

This cmdline prints twice for me.

If I do:

echo "<command>"; `!#:0-$`

This works for me..

Comment by unixmonkey20949 321 weeks ago

Your point of view

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