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This is an alternative to another command using two xargs. If it's a command you know there's only one of, you can just use:
ls -l /proc/$(pgrep COMMAND)/cwd
There is 1 alternative - vote for the best!
Invoked from within a shell script, this will print the directory in which the script resides. Doesn't depend on external tools, /proc/self/*, etc.. (`echo` is a shell builtin.) To see the *current working* directory of a script, use `pwd`.
I submitted a command like this without $0 if $BASH_SOURCE is unset. Therefor, it did only work when using ./script, not using 'sh script'. This version handles both, and will set $mydir in a script to the current working directory. It also works on linux, osx and probably bsd.
The pwdx command reports the current working directory of a process or processes.
If you can do better, submit your command here.
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The above command didn't work for me. I need to add the double quotation to make it work
eval "ls -l /proc/{$(pgrep -d, bash)}/cwd"
Interesting. It works for me without the quotes on CentOS 5.5, bash v3.2.25(1) and OpenSUSE 11.4 bash v 4.1.10(1). It also worked on zsh 4.3.10 without quotes. What shell and version didn't it work on?
eval is not needed. Just type 'ls -l /proc/$(pgrep -d, X)/cwd'
chmurli, your version works if there is one process running for the command, in which case you don't need the "-d," either. If you notice, I had mentioned that in the comments. If there is more than one process, you need the curly braces and the comma, and you need the eval.