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There is 1 alternative - vote for the best!
Invoked from within a shell script, this will print the directory in which the script resides. Doesn't depend on external tools, /proc/self/*, etc.. (`echo` is a shell builtin.) To see the *current working* directory of a script, use `pwd`.
This is an alternative to another command using two xargs. If it's a command you know there's only one of, you can just use:
ls -l /proc/$(pgrep COMMAND)/cwd
I submitted a command like this without $0 if $BASH_SOURCE is unset. Therefor, it did only work when using ./script, not using 'sh script'. This version handles both, and will set $mydir in a script to the current working directory. It also works on linux, osx and probably bsd.
The pwdx command reports the current working directory of a process or processes.
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Unless the path is a link, readlink doesn't echo the path by default. It needs either '-e' or '-m' to echo whether or not the path is to a link.
/proc/self/cwd is always a symlink (man proc)
This is not really an "alternative" to some of the others, as this is the current working directory of the *current* process. A couple of the earlier alternatives are for finding the working directory of some other command, such as the apache executable or the currently running vim commands.
Your version is almost the same as the much simpler $PWD (or pwd command), except yours returns the canonical version of the directory which is handy. You could accomplish the same with
readlink -f $PWDbut that's not really easier.