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In order to create, let's say, 10 directories with a single process we can use the command:
mkdir test{1,2,3,4,5,6,7,8,9,10}
something extremely boring to type! Why not use seq?
seq -s, 1 10
and use its output inside the curly braces?
The obvious solution
mkdir test{$(seq -s, 1 10)}
is, unfortunately, too naive and doesn't work. The answer is the order of the shell expansions (feature of Bourne Shell, actually), where brace expansion happens before command substitution (according to Bash's manual).
The solution is to put another level of substitution, using the powerful and mystic command eval.
I found the trick in a similar problem in the post at http://stackoverflow.com/questions/6549037/bash-brace-expansion-in-scripts-not-working-due-to-unwanted-escaping
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lol, what bash versions you use?
mkdir test{1..10} works fineI'm sorry that didn't clarify enough my point, but I DON'T want to type these numbers in the command line. For example, I could use shell parameters or get another output from a program, which produces for example words and not numbers.
But, yes, of course, what you've written works perfectly fine on most recent versions of Bash! It's the hard-wired numbers that are unwanted here...
Sorry, I didn't get it. You used "1" and "10", I used the same 2 numbers, not whole sequence. What's the difference?
Ok, say you need something like this:
seq -s, 1 4 1000How, are you going to write it?
Or, let's say you're creating the directories "lonely", "closely", "finally" and all these names are stored in a shell variable, or can be extracted from another program.
The numbers here are just an example. A simple, and maybe not very suitable, example. They don't really have any special meaning.
>you need something like this:
>seq -s, 1 4 1000
The answer is
echo {1..100..4},