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Access variables inside a - piped while - loop

Terminal - Access variables inside a - piped while - loop
while read line; do echo $line; done <<< "$var"
2011-09-22 16:53:32
User: totti
Functions: echo read
-5
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Access variables inside a - piped while - loop

Consider the following simple situation [ reading something using while and read ]

[See script 1 in sample output]

---------------------------------------------------

The variable var is assigned with "nullll" at first. Inside the while loop [piped while] it is assigned with "whillleeee". [Onlly 2 assignments stmts]. Outside the loop the last assigned value for "var" [and no variable] inside the while can't be accessed [Due to pipe, var is executed in a sub shell].

In these type of situation variables can be accessed by modifying as follows.

[See script 2 in sample output]

___________________________

Vary helpful when reading a set of items, say file names, stored on a file [or variable] to an array an use it later.

Is there any other way 2 access variables inside and outside the loop ??

Show sample output | Add to favourites | Report as malicious

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