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Remove the first and the latest caracter of a string

Terminal - Remove the first and the latest caracter of a string
var=:foobar:; echo ${var:1:-1}
2011-11-19 03:33:46
User: sputnick
Functions: echo
9
Remove the first and the latest caracter of a string

Alternatives

There is 1 alternative - vote for the best!

Terminal - Alternatives
echo foobar | sed -r 's/(^.|.$)//g'
2011-11-19 16:19:07
User: ebraminio
Functions: echo sed
Tags: bash sed
0

Just an other solution :)

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What others think

Not working on Centos! I got

#var=:foobar:; echo ${var:1:-1}

-bash: -1: substring expression < 0

Comment by dynaguy 182 weeks and 4 days ago

@dynaguy, what is your shell ? You can know it by sending in your shell

cat /proc/$$/cmdline

And the version :

echo $SHELL -version
Comment by sputnick 182 weeks and 4 days ago

oops, typo :

$SHELL -version
Comment by sputnick 182 weeks and 4 days ago

[root@atom ~]# $SHELL -version

GNU bash, version 3.2.25(1)-release (i686-redhat-linux-gnu)

Copyright (C) 2005 Free Software Foundation, Inc.

I tested on Ubuntu and it works. But not work on CentOS 6.0 32bit. Here is the CentOS:

[root@atom ~]# $SHELL -version

GNU bash, version 3.2.25(1)-release (i686-redhat-linux-gnu)

Copyright (C) 2005 Free Software Foundation, Inc.

[root@atom ~]# $SHELL -version

GNU bash, version 3.2.25(1)-release (i686-redhat-linux-gnu)

Copyright (C) 2005 Free Software Foundation, Inc.

Comment by dynaguy 182 weeks and 4 days ago

Your point of view

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