find the biggest files recursively, no matter how many

find . -type f|perl -lne '@x=sort {$b->[0]<=>$a->[0]}[(stat($_))[7],$_],@x;splice(@x,11);print "@{$x[0]}";END{for(@x){print "@$_"}'
A different approach to the problem - maintain a small sorted list, print the largest as we go, then the top 10 at the end. I often find that the find and sort take a long time, and the large file might appear near the start of the find. By printing as we go, I get better feedback. The sort used in this will be much slower on perls older than 5.8.
Sample Output
4833673216 ./Downloads/gnome-2.29.20091103-x86/gnome-2.29.20091103-x86.vmdk

-2
By: bazzargh
2012-01-08 14:43:43

1 Alternatives + Submit Alt

  • This command will find the biggest files recursively under a certain directory, no matter if they are too many. If you try the regular commands ("find -type f -exec ls -laSr {} +" or "find -type f -print0 | xargs -0 ls -laSr") the sorting won't be correct because of command line arguments limit. This command won't use command line arguments to sort the files and will display the sorted list correctly. Show Sample Output


    10
    find . -type f -printf '%20s %p\n' | sort -n | cut -b22- | tr '\n' '\000' | xargs -0 ls -laSr
    fsilveira · 2009-08-13 13:13:33 5

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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