Across an entire subtree, list not-empty directories that have no child-directories, globally sorted by their respective mtime

ls -ltr --directory $(find . -regex "./.*[^/]*\'" -type f | xargs -n 1 dirname | sort | uniq)
This let me find some a set of modifications that were made to a rather large tree of files, where the file-names themselves were not unique (actually: insanely redundant and useless. "1.dat 2.dat ..."). Pruning down to last-branch brough things back to the "project-name" scope, and it's then easy to see which branches of the tree have recently changed, or any other similar search. Ideally, it should sort the directories by the mtime of the most recent *file* *inside* the directory, but that's probably outside the scope of a (sane...) command line.

0
By: pdkl95
2012-03-02 03:48:47

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What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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