count processes with status "D" uninterruptible sleep

top -b -n 1 | awk '{if (NR <=7) print; else if ($8 == "D") {print; count++} } END {print "Total status D: "count}'

4
By: jcgam69
2009-02-19 21:14:46

2 Alternatives + Submit Alt

What Others Think

Alright smart guy, how would I create said uninterruptible sleeping process? Vote up BTW
Williebee · 487 weeks and 3 days ago
Pull the plug on an NFS server. Processes that attempt to read from the NFS file system will block in state "D" until the NFS server returns, or the system is rebooted. (Blatantly plagiarized from the web because I didn't know either).
jcgam69 · 487 weeks and 2 days ago
I'm not quite getting this awk. You want to always print the first seven lines of output regardless of the state? Also you don't want to know if the state *IS* D, but you want to know if it contains D. This would be fixed with: awk '$8 ~ /D/{print}'
wxl · 134 weeks and 4 days ago
I'm not quite getting this awk. You want to always print the first seven lines of output regardless of the state? Also you don't want to know if the state *IS* D, but you want to know if it contains D. This would be fixed with: awk '$8 ~ /D/{print}'
wxl · 134 weeks and 4 days ago
oops error with the server and i can't delete. boo.
wxl · 134 weeks and 4 days ago

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