Get the date for the last Saturday of a given month

cal 04 2012 | awk 'NF <= 7 { print $7 }' | grep -v "^$" | tail -1
This is a little trickier than finding the last Sunday, because you know the last Sunday is in the first position of the last line. The trick is to use the NF less than or equal to 7 so it picks up all the lines then grep out any empty lines.
Sample Output
28

2 Alternatives + Submit Alt

What Others Think

Uh, not sure. It's May here and I get last day of the current month. 31 using cal 04 2012 | awk '{ $7 && X=$7 } END { print X }
Habitual · 336 weeks and 5 days ago
@habitual: that's what the '04' parameter is: April. Replace it with 05 for May.
flatcap · 336 weeks and 5 days ago
flatcap: But what if I WANT the last day of 04?
Habitual · 336 weeks and 4 days ago
I think cal now supports knowing the first day of the week depending on your _NL_TIME_WEEK_1STDAY. Does your output of `cal 05 2012` equal: May 2012 Su Mo Tu We Th Fr Sa 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31
ClashTheBunny · 335 weeks and 2 days ago

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