Get the date for the last Saturday of a given month

desiredDay=6; year=2012; month=5; n=0; while [ $(date -d "$year-$((month+1))-1 - $n day" "+%u") -ne $desiredDay ]; do n=$((n+1)); done; date -d "$year-$((month+1))-1 - $n day" "+%x"

Choosing your year and month. You only need the gnu date command and bash. desiredDay of the week is (1..7); 1 is Monday. If you want desiredDay of week (0..6); 0 is Sunday

desiredDay=6; year=2012; month=5; n=0; while [ $(date -d "$year-$((month+1))-1 - $n day" "+%w") -ne $desiredDay ]; do n=$((n+1)); done; date -d "$year-$((month+1))-1 - $n day" "+%x"

Sample Output

05/26/2012

By: ClashTheBunny

2012-05-17 12:02:30

date Date manipulation bash date

2 Alternatives + Submit Alt

Get the date for the last Saturday of a given month

If your locale has Monday as the first day of the week, like mine in the UK, change the two $7 into $6 Show Sample Output
This is sample output - yours may be different.
```
28
```
2

cal 04 2012 | awk '{ $7 && X=$7 } END { print X }'

flatcap · 2012-05-06 23:43:21 40
Get the date for the last Saturday of a given month

This is a little trickier than finding the last Sunday, because you know the last Sunday is in the first position of the last line. The trick is to use the NF less than or equal to 7 so it picks up all the lines then grep out any empty lines. Show Sample Output
This is sample output - yours may be different.
```
28
```
-2

cal 04 2012 | awk 'NF <= 7 { print $7 }' | grep -v "^$" | tail -1

javidjamae · 2012-05-03 16:57:45 767

What Others Think

rahimhh21 · 106 weeks and 5 days ago

Perfecthomepugs · 97 weeks and 5 days ago

pugpuppies95 · 59 weeks and 4 days ago

yeneba6574 · 12 weeks and 6 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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