This type of join is clearly documented in the bash manual. Only the first character of IFS is used for the delimiter. Show Sample Output
DOCKER_APP_VARS=(DATABASE_USER=dbuserro, DATABASE_PASSWORD=maipass)
[jeff@omniscience container] (master)$ echo docker run $(printf -- " -e %s" ${DOCKER_APP_VARS[*]}) -name 12factorapp mattdm/fedora-small
docker run -e DATABASE_USER=dbuserro, -e DATABASE_PASSWORD=maipass -name 12factorapp mattdm/fedora-small
Note that the printf method by itsself doesn't include a newline (\n), so you'll need to embed it into an echo statement or something that does.
Show Sample Output
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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