Print data from field 9 till the end separated by a white space and new record separated by newline.

awk '{for (i=9;i<=NF;i++) {printf "%s",$i; printf "%s", " ";}; printf "\n"}'
It'll print the file names preserving the spaces in their names and adding new line after every new filename. I wrote this to quickly find out how many files in any directory is owned by a particular user. This can be extended using pipe and grep to do much more.
Sample Output 
$ ls -l
total 476
-rw-rw-r-- 1 aditya aditya  38543 Jan  7 17:06 a.pdf
-rw-rw-r-- 1 aditya aditya  50665 Dec  9 11:42 H.pdf
-rw-rw-r-- 1 aditya aditya   5769 Dec  9 11:18 h b.pdf
-rw-rw-r-- 1 aditya aditya  98084 Dec  9 11:28 M.pdf
-rw-rw-r-- 1 aditya aditya  53475 Jan  6 15:45 R E.pdf
-rw-rw-r-- 1 aditya aditya  39996 Dec  9 11:23 R E1.pdf
-rw-rw-r-- 1 aditya aditya 124566 Nov 20 08:58 R I.pdf
-rw-rw-r-- 1 aditya aditya  59557 Dec  7 23:29 Welcome.pdf

$ ls -l | awk '{for (i=9;i<=NF;i++) {printf "%s",$i; printf "%s", " ";}; printf "\n"}'

a.pdf 
H.pdf 
h b.pdf 
M.pdf 
R E.pdf 
R E1.pdf 
R I.pdf 
Welcome.pdf

0
By: adimania
2013-02-12 13:57:43
awk printf awk
0
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