find /some/path -type f -printf '%f\n'
instead of
find /some/path -type f | gawk -F/ '{print $NF}'
100 txt 25 gz 10 vim 3 gitignore
... plus do a sort according frequency Show Sample Output
Works on current directory, with built-in sorting. Show Sample Output
Get the longest match of file extension (Ex. For 'foo.tar.gz', you get '.tar.gz' instead of '.gz') Show Sample Output
Just a little simplification.
If your grep doesn't have an -o option, you can use sed instead.
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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