Find top 5 big files

find . -type f -exec ls -s {} \; | sort -n -r | head -5
Find top 5 big files

-3
By: opexxx
2013-03-19 12:16:24

2 Alternatives + Submit Alt

  • zsh: list of files sorted by size, greater than 100mb, head the top 5. '**/*' is recursive, and the glob qualifiers provide '.' = regular file, 'L' size, which is followed by 'm' = 'megabyte', and finally '+100' = a value of 100


    1
    ls -Sh **/*(.Lm+100) | tail -5
    khayyam · 2013-03-21 20:22:11 0
  • This command is more robust because it handles spaces, newlines and control characters in filenames. It uses printf, not ls, to determine file size.


    -4
    count=0;while IFS= read -r -d '' line; do echo "${line#* }"; ((++count==5)) && break; done < <(find . -type f -printf '%s %p\0' | sort -znr)
    sharfah · 2013-03-19 17:19:26 0

What Others Think

You're better to use: find -type f -print0 | xargs -0 ls -s | sort -n -r | head -n 5 which will avoid running `ls` for every filename (it'll group them).
wejn · 291 weeks and 2 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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