Display the human-readable sizes of all files and folders in the current directory with 3 decimal places

du -Lsbc * |awk 'function hr(bytes){hum[1024**4]="TiB";hum[1024**3]="GiB";hum[1024**2]="MiB";hum[1024]="kiB";for(x=1024**4;x>=1024;x/=1024){if(bytes>=x){return sprintf("%8.3f %s",bytes/x,hum[x]);}}return sprintf("%4d B",bytes);}{print hr($1) "\t" $2}'
To sort the list by file/directory size, insert `sort -n |` before `awk`.
Sample Output
   9.543 MiB	bin
   4.000 kiB	boot
  28.323 kiB	dev
  66.523 MiB	etc
 151.247 GiB	home
  17.196 MiB	lib
  17.196 MiB	lib64
   4.000 kiB	media
   4.000 kiB	mnt
   8.000 kiB	opt
 376.264 MiB	root
   4.358 MiB	sbin
   4.000 kiB	selinux
   4.000 kiB	srv
  10.098 MiB	sys
   2.693 MiB	tmp
   2.244 GiB	usr
  72.920 GiB	var
 226.903 GiB	total

By: nst
2013-08-18 02:28:18

What Others Think

Nice one. Just for completeness I'll add the code with the sorted output: du -Lsbc * | sort -n -k1,1 | awk 'function hr(bytes) {hum[1024**4]="TiB";hum[1024**3]="GiB";hum[1024**2]="MiB";hum[1024]="kiB";hum[1]="B"; for (x=1024**3;x>=1;x/=1024) {if (bytes>=x){return sprintf("%8.3f %s", bytes/x, hum[x]);}}} {print hr($1) "\t" $2}'
erix · 414 weeks and 3 days ago
Cool but it doesn't address zero length files, just leaves them hanging in the wrong column spot.
pnelsonsr · 414 weeks and 3 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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