Loop over the days of a month, in $YYYY$MM$DD format

YYYY=2014; MM=02; for d in $(cal -h $MM $YYYY | grep "^ *[0-9]"); do DD=$(printf "%02d" $d); echo $YYYY$MM$DD; done
Edit YYYY and MM at the beginning of the command with the year and month you want. Note that `DD=$(printf "%02d" $d)` will pad single digit integers with a leading zero. Substitute `echo $YYYY$MM$DD` at the end of the line with the command you want to launch, for instance script.pl --yyyymmdd $YYYY$MM$DD Also available on GitHub as bash util: https://github.com/fibo/yyyymmdd
Sample Output

By: fibo
2014-02-06 11:31:57

1 Alternatives + Submit Alt

What Others Think

Very nice. I can offer one small improvement and one alternate way of formatting. | tail -6 | head -5 can be replaced with grep (saving one command): | grep "^ *[0-9]" Some (or none) leading space, followed by numbers. "printf" is a shell builtin so it's already quick, but the alternative bash way is: [ ${#DD} = 1 ] && DD=0$DD If DD has length 1, then prefix it with a zero. So my command looks like: YYYY=2014; MM=02; for DD in $(cal $MM $YYYY | grep "^ *[0-9]"); do [ ${#DD} = 1 ] && DD=0$DD; echo $YYYY$MM$DD; done
flatcap · 402 weeks and 1 day ago
@flatcap: thank you for your improvement. I replaced the first submitted version ``` YYYY=2014; MM=02; for d in $(cal $MM $YYYY | tail -6 | head -5); do DD=$(printf "%02d" $d); echo $YYYY$MM$DD; done ``` adding grep "^ *[0-9]" as you suggested. About prefixing with leading zero, I prefer printf, so you can even change format if you want, just editing "%02d".
fibo · 399 weeks and 1 day ago
Is there any way to modify this command to include the day names? i.e. ``` 2014-02-01 SA 2014-02-02 SU 2014-02-03 MO 2014-02-04 TU 2014-02-05 WE ``` after looking through the commands for cal I haven't had luck myself.
banj · 388 weeks and 3 days ago

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