Write a shell script that removes files that contain a string

find . | xargs grep -l "FOOBAR" | awk '{print "rm -f "$1}' > doit.sh
After this command you can review doit.sh file before executing it. If it looks good, execute: `. doit.sh`

2014-04-06 15:48:41

2 Alternatives + Submit Alt

What Others Think

Hmm... You don't need find and xargs at the beginning. grep can search recursively: grep -rl "FOOBAR" | ... However if any of the file/dirnames contain whitespace, everything goes badly wrong. Here's my version (quoting the filenames): grep -rl "FOOBAR" | sed 's/.*/rm -f "\0"/' > doit.sh
flatcap · 392 weeks and 6 days ago
grep -rl "FOOBAR" | xargs -L1 echo "rm -rf $1" > doit.sh
bmx666 · 392 weeks and 5 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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