look what's running

for a in $(ls /usr/sbin /usr/bin); do ps -fC $a;done|grep -v PPID
Thanks to pooderbill for the idea :-)
Sample Output
root      1199     1  0 09:14 ?        00:00:00 mdm
root      1508  1199  0 09:14 ?        00:00:00 mdm
root       827     1  0 09:14 ?        00:00:00 /usr/sbin/ModemManager
root       878     1  0 09:14 ?        00:00:00 NetworkManager
root      1741     1  0 09:14 ?        00:00:00 nmbd -D
syslog     808     1  0 09:14 ?        00:00:00 rsyslogd

-2
By: knoppix5
2015-04-27 18:15:56

1 Alternatives + Submit Alt

What Others Think

Interesting command... However, it's terrifyingly inefficient. On my dev box: ls /usr/bin /usr/sbin | wc -w 4035 That means I'm running ps over 4000 times! It takes nearly a minute to run. . My first thought was trawling through /proc, looking at the exe link, but that requires root privs for root processes. . ps -p $(find /proc -path /proc/\*/exe -maxdepth 2 -printf "%p %l\n" 2> /dev/null | awk -F/ '($5$6 ~ "usrs*bin") { print $3; }' | paste -s -d,) It looks in /proc for the 'exe' symlinks to the commands; it filters out the exe locations; it joins them up and gives them to 'ps -p' . *Very* ugly, but it does run instantly!
flatcap · 181 weeks ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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