shell function to create an 'invisible regex' that won't show up when grepping the output from 'ps'

ir() { perl -pne 's/(.)(.*)/\[\1]\2/' <<< "$@" ;}
Note that `grep "$(ir foo)"` really doesn't save any typing, but wrapping this inside a second shell function will: psg() { grep "$(ir \"$@\")" ;}
Sample Output
$ ir foo
[f]oo

$ ps aux | grep "$(ir foo)"
[returns nothing]

-1
By: bartonski
2015-07-25 14:13:33

What Others Think

Perl? Ha! I laugh at your perl. Here's ir() using only shell script (shorter and faster :-) ir1() { echo "[${1:0:1}]${1:1} ${@:2}"; } . Take variable $1 (offset 0, 1 character) ${1:0:1} Wrap it in [] [${1:0:1}] Add the rest of variable $1 (offset 1 to the end) ${1:1} . Next show the rest of the parameters ($@ is an array), so this means $2 $3 etc ${@:2}
flatcap · 165 weeks and 1 day ago
or you could just use character class like ps aux | grep [p]rogram it will make the 'p' a regex character class containing only the letter 'p' and will show in ps output as '[p]rogram', but will only search for 'program'
obayemi · 163 weeks and 3 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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