Print all open regular files sorted by the number of file handles open to each.

sudo lsof | egrep 'w.+REG' | awk '{print $10}' | sort | uniq -c | sort -n
This command run fine on my Ubuntu machine, but on Red Hat I had to change the awk command to `awk '{print $10}'`.

2015-08-18 14:09:02

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What Others Think

Hmm... It's a nice idea, but your parsing of lsof is flawed. . What are you trying to match with egrep? 'w.+REG' means the letter 'w' then 'REG' later. Do you mean 'w +REG' ('w' at the end of the FD column, then whitespace, then 'REG')? . I was going to suggest dropping egrep and search using awk, e.g. ... | awk '($5 == 'REG') {'print $10'} | ... but then I spotted a bigger problem... . Here's some output from my machine: lsof | egrep 'w.+REG' | grep audit auditd 932 root 4w REG 253,1 3656976 265841 /var/log/audit/audit.log auditd 932 940 root 4w REG 253,1 3656976 265841 /var/log/audit/audit.log . Both threads of auditd have an open handle to the log file. The TID (thread id) is missing from the parent thread, so that line has only 9 columns. The child thread output has 10 columns. . This means your command counts up lots of blanks lines that ought to be files.
flatcap · 311 weeks and 2 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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