mkdir() { /bin/mkdir $@ && eval cd "\$$#"; }

Go to the created directory after using mkdir


-7
By: fnando
2009-03-30 17:24:21

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What Others Think

Why not just "mkdir blahblahblah && cd !$"?
cbilson · 477 weeks and 1 day ago
I use vi mode. mkdir /path/to/dir <esc(mapped to caps)>kcwcd<enter>
jnash · 477 weeks and 1 day ago
bad form: you should never make an alias or function that is named after an already preserved name. 'mkcd' would be more appropriate.
atoponce · 477 weeks and 1 day ago
@cbilson That doesn't actually work. Bash replaces the !$ before running the command, so it will not likely be the cd command, and will be something like cat file-from-before mkdir blahblahblah && cd cat file-from-before which is not as intended. I saw some other post with this trick: (mkdir blahblahblah) && cd !$ which will work as expeted, since the subshell runs first, so the last command IS indeed the mkdir.
clockworkavian · 477 weeks and 1 day ago
er.. my fix didn't work either. I must have missed some syntax.
clockworkavian · 477 weeks and 1 day ago
@clockworkavian mkdir tmp && cd !$ worked for me. What bash are you using?
Highwayman · 477 weeks and 1 day ago
3.2-5ubuntu1, the default for ubuntu 9.04 just to make sure I'm not crazy, I just ran cat blank mkdir tmp && cd !$ and it did indeed expand to mkdir tmp && cd blank I wonder if there's a shell option somewhere that affects this.
clockworkavian · 477 weeks and 1 day ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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