Print only the odd lines of a file

awk '{if (NR % 2 == 1) print $0}' file.txt

2009-02-05 18:43:19

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What Others Think

Downvoted for useless use of cat. Use "command
Rhomboid · 636 weeks and 6 days ago
And now I see that this comment form doesn't allow braces, mangling the comment.
Rhomboid · 636 weeks and 6 days ago
@Rhomboid - try prefixing your command with $. awk '{if (NR % 2 == 1) print $0}' file.txt
DEinspanjer · 636 weeks and 6 days ago
Fixed. Thanks.
twopoint718 · 636 weeks and 6 days ago
Odd: awk 'NR % 2 == 1' file.txt Even: awk 'NR % 2 == 0' file.txt
systemj · 636 weeks and 6 days ago
Odd: awk NR%2 file.txt Even: awk 1-NR%2 file.txt
unbibium · 636 weeks and 6 days ago
Another way: awk '{print;getline}' file.text # ODD awk 'getline{print}' file.text # EVEN
porges · 636 weeks and 6 days ago
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looneyhans · 9 weeks ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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