Chronometer in hour format

stf=$(date +%s.%N);for ((;;));do ctf=$( date +%s.%N );echo -en "\r$(date -u -d "0 $ctf sec - $stf sec" "+%H:%M:%S.%N")";done
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Sample Output

2017-01-26 14:31:33

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What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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