combine `mkdir foo && cd foo` into a single function `mcd foo`

function mcd() { [ -n "$1" ] && mkdir -p "$@" && cd "$1"; }
I find that I create a directory and then cd into that directory quite often. I found this little function on the internets somewhere and thought I'd share it. Just copy-paste it into you ~/.bash_profile and then `source ~/.bash_profile`.
Sample Output
user@home:~$ mcd newdirectory
user@home:newdirectory $

2009-05-20 16:41:48

4 Alternatives + Submit Alt

What Others Think

I think there's a mistake, it should be: function mcd() { [ -n "$1" ] && mkdir -p "$1" && cd "$1"; } because other wise when you type "mcd blah test" it creates /blah and /test and goes into /blah. But it depends if that was the intended behavior or not...
Weboide · 689 weeks and 2 days ago
the point is that you want to create a directory AND move into that directory at the same time. giving mcd two arguments is kind of like saying you want to create two directories AND move into two directories in the same command. of course, moving into two directories simultaneously is nonsense. but you have a good point, which ought to be taken into consideration if you're going to use this function. i could see, perhaps, adding another test to the function to look for the presence of a second argument and then displaying a "usage" message.
thebillywayne · 689 weeks and 1 day ago
The below would do that jod : md () { mkdir -p "$1" && cd "$1"; }
hemanth · 679 weeks and 4 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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