Show the last 20 sessions logged on the machine

last -n 20
change 20 by the number of sessions you want to know (20 it's fair enough)
Sample Output
root     pts/0        137.218.16.20    Tue May 26 22:02   still logged in   
reboot   system boot  2.4.27-3-386     Tue May 26 20:56          (01:06)    
root     pts/0        137.218.16.20    Tue May 26 20:22 - down   (00:33)    
reboot   system boot  2.4.27-3-386     Thu May 21 07:32         (5+13:23)   
root     pts/1        137.218.16.20    Sat May 16 22:36 - 22:54  (00:18)

1
By: jipipayo
2009-05-26 22:09:09

These Might Interest You

  • Short and sweet command. This command is also useful for other information such as what IP address a particular user logged in from, how long had they been logged in, what shell do they use.


    -1
    w
    haivu · 2009-03-24 16:03:28 1
  • In my work environment, we log onto the servers as our user ('user', in the sample ouput), and 'sudo su - root' to other accounts. This trick allows us to return the account name we logged in as -- and not the account name we currently are ('root', in this example). Using this trick, you can build other commands: Set your CVSROOT env variable to your account name: CVSROOT=$(who am i | awk '{print $1}')@cvs.server.example.com:/cvsroot SCP a file to another server: scp file.txt $(who am i | awk '{print $1}')@some.other.server.com:. This works out great in my environment, as we can include this in our documentation and make the comands more easy to copy/paste for different users, and not have to set all sorts of variables, or modify the docs for each user. whoami gives you the name of the user you currently are, not the user you logged on originally as. who gives you a listing of every single person logged onto the server. who am i gives you the name of the user you logged on as, and not who you changed to with su. Look at the following scenario: whoami user su - # whoami root # who am i user pts/51 2009-02-13 10:24 (:0.0) whoami != who am i Show Sample Output


    -18
    who am i
    ozymandias · 2009-02-20 16:26:11 9

  • 0
    TTY=$(tty | cut -c 6-);who | grep "$TTY " | awk '{print $6}' | tr -d '()'
    sharfah · 2010-08-06 13:42:17 3
  • This is different that `who` in that who only cares about logged-in users running shells, this command will show all daemon users and what not; also users logged in remotely via SSH but are running SFTP/SCP only and not a shell. Show Sample Output


    1
    ps aux | sed -n '/USER/!s/\([^ ]\) .*/\1/p' | sort -u
    infinull · 2010-02-10 05:56:26 2

What Others Think

You can get rid of the "-n " and save 2 characters :P. last -20 is just the same
skinp · 469 weeks and 3 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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