Scan all open ports without any required program

for i in {1..65535}; do (echo < /dev/tcp/127.0.0.1/$i) &>/dev/null && printf "\n[+] Open Port at\n: \t%d\n" "$i" || printf "."; done

6
By: emphazer
2019-05-21 09:34:15

What Others Think

Nice, but too many dots, information gets lost. Scan any IP, report only open ports: ip=192.168.1.254;for i in {1..65535}; do (echo < /dev/tcp/$ip/$i) &>/dev/null && printf "\n[+] Open TCP Port at: \t%d\n" "$i"; done
test666v2 · 20 weeks and 5 days ago
indeed, your is better ;-)
emphazer · 20 weeks and 3 days ago
Hi, did you ever hear about nmap tool? I'd suggest simply to: nmap localhost
chvdr · 18 weeks and 2 days ago
Hi I change this a little now this show just open ports :) for i in {1..65535}; do (echo < /dev/tcp/127.0.0.1/$i) &>/dev/null && printf "\n[+] Open Port at\n: \t%d\n" "$i" || printf "."; done| grep -i "[0-9]"
karakral · 17 weeks and 6 days ago
Hi I change this a little now this show just open ports :) for i in {1..65535}; do (echo < /dev/tcp/127.0.0.1/$i) &>/dev/null && printf "\n[+] Open Port at\n: \t%d\n" "$i" || printf "."; done| grep -i "[0-9]"
karakral · 17 weeks and 6 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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