A command's package details

dpkg -S `which nm` | cut -d':' -f1 | (read PACKAGE; echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | less
In Debian based distros, this command will list 'binutils' package details which contains 'nm' command. You can replace 'nm' to any other command.

By: mohan43u
2009-07-14 20:21:48

2 Alternatives + Submit Alt

  • This version builds on my command 8776 (Find the package a command belongs to on debian-based distros). So if you use that command to find package name then you could alternatively use following for package summary: function summpkg { dpkg -s $(whichpkg $1 | awk -F: '{print $1}'); } Show Sample Output

    function summpkg { dpkg -s $(dpkg -S $1 | egrep -w $(which $1)$ | awk -F: '{print $1}') ; }
    b_t · 2011-07-05 23:06:37 0
  • Find information about the rpm package which owns a certain file. Show Sample Output

    summpkg() { rpm -qfi "$@"; }
    flatcap · 2011-07-05 23:39:24 2

What Others Think

dlocate claims to be faster for some of these operations, although it returns more matches in the case of 'dlocate -S /usr/bin/nm'. Nice command!
bwoodacre · 671 weeks and 3 days ago
You can simplify this slightly to eliminate "read": dpkg -S `which nm` | cut -d':' -f1 | (read PACKAGE; echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | less Personally I'd leave out the dpkg -L call and less, and keep it short: cmd(){ PACKAGE=$(dpkg -S $(which $1) | cut -d':' -f1); echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}" ;}
johnraff · 650 weeks and 3 days ago
er... sorry I mispasted the first line, it should have been: PACKAGE=$(dpkg -S $(which nm) | cut -d':' -f1 ); echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | less
johnraff · 650 weeks and 3 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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