A command's package details
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This version builds on my command 8776 (Find the package a command belongs to on debian-based distros). So if you use that command to find package name then you could alternatively use following for package summary:
function summpkg { dpkg -s $(whichpkg $1 | awk -F: '{print $1}'); }Show Sample Output0function summpkg { dpkg -s $(dpkg -S $1 | egrep -w $(which $1)$ | awk -F: '{print $1}') ; } -
Find information about the rpm package which owns a certain file. Show Sample Output
0summpkg() { rpm -qfi "$@"; }
What do you think?
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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dpkg -S `which nm` | cut -d':' -f1 | (read PACKAGE; echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | lessPersonally I'd leave out the dpkg -L call and less, and keep it short:cmd(){ PACKAGE=$(dpkg -S $(which $1) | cut -d':' -f1); echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}" ;}PACKAGE=$(dpkg -S $(which nm) | cut -d':' -f1 ); echo "[${PACKAGE}]"; dpkg -s "${PACKAGE}"; dpkg -L "${PACKAGE}") | less