Recursive replace of directory and file names in the current directory.

find . *oldname* | grep oldname | perl -p -e 's/^(.*)(oldname)(.*$)/mv $1$2$3 $1newname$3/' | sh
This should work anywhere perl and grep is available. :P

1
By: pravus
2009-07-26 01:22:24

2 Alternatives + Submit Alt

What Others Think

a) find . *oldname* will print every frickin file in the tree, and then print *oldname*: no such file or directory. Maybe you mean find -name "*oldname*" b) piping something to grep and then to one of the following is ALWAYS a waste: sed, awk, perl. You can get rid of grep and convert your perl to: perl -n -e '/^(.*)(oldname)(.*$)/ && print "mv $& $1newname$3\n"'
0x89 · 620 weeks and 6 days ago
You are assuming a) That that is unintentional. :P It is a lazy way of tracking what filenames were changed in case I made a mistake with oldname. b) Ya, that part is better.
pravus · 620 weeks and 6 days ago
At least in the debian/ubuntu perl distribution there is a prename command (replacing util-linux rename) which would do this for you in one shot using find: find . -name "*oldname*" -exec prename 's/oldname/newname/' {} + If you are not quoting the *oldname* expression then find is matching only files&directories in the current directory because the shell is expanding *oldname* before find even gets called.
bwoodacre · 620 weeks and 5 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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