find the biggest files recursively, no matter how many
-rw-r--r-- 1 fsilveira fsilveira 542537728 2001-10-03 19:29 ./rh72/enigma-SRPMS-disc2.iso -rw-r--r-- 1 fsilveira fsilveira 624476160 2001-10-03 19:35 ./rh72/enigma-docs.iso -rw-r--r-- 1 fsilveira fsilveira 669429760 2001-10-03 19:24 ./rh72/enigma-i386-disc2.iso -rw-r--r-- 1 fsilveira fsilveira 677961728 2001-10-03 19:22 ./rh72/enigma-i386-disc1.iso -rw-r--r-- 1 fsilveira fsilveira 680282112 2001-10-03 19:27 ./rh72/enigma-SRPMS-disc1.iso
1 Alternatives + Submit Alt
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A different approach to the problem - maintain a small sorted list, print the largest as we go, then the top 10 at the end. I often find that the find and sort take a long time, and the large file might appear near the start of the find. By printing as we go, I get better feedback. The sort used in this will be much slower on perls older than 5.8. Show Sample Output
-2find . -type f|perl -lne '@x=sort {$b->[0]<=>$a->[0]}[(stat($_))[7],$_],@x;splice(@x,11);print "@{$x[0]}";END{for(@x){print "@$_"}'
What do you think?
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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find . -type f -ls | sort -n --key=7Pipe that to "cut -b68-" to get only the filenames.find . -type f -printf '%s\t"%p"\n' | sort -n | cut -f2 | xargs ls -laSthe tab is for cut and the quotes for xargs. Another option: on a single fs, use inode numbers to avoid messy filenames.find -type f -print0 | xargs -0 ls -la | sort -nr --key=5this handles ANY type of filename even those with newlines and spaces.