function sepath { echo $PATH |tr ":" "\n" |sort -u |while read L ; do cd "$L" 2>/dev/null && find . \( ! -name . -prune \) \( -type f -o -type l \) 2>/dev/null |sed "s@^\./@@" |egrep -i "${*}" |sed "s@^@$L/@" ; done ; }

search for a file in PATH

search argument in PATH accept grep expressions without args, list all binaries found in PATH
Sample Output
$ sepath noo
/usr/openwin/bin/ttsnoop
/usr/sbin/snoop
$ sepath ^ps$
/bin/ps
/usr/bin/ps
/usr/ucb/ps

-1
By: mobidyc
2009-09-11 15:03:22

3 Alternatives + Submit Alt

What Others Think

Don't sort the path because there may be two programs with the same name and the first in the path should show up first. Also, take advantage of grep regular expression and remove the sed scripts. Handle empty string cases. function sepath { echo ${PATH} | tr : \\n | while read L; do find ${L:-"."} -type d ! -path ${L:-"."} -prune -o \( -type f -o -type l \) 2>/dev/null | grep -i "${L:-"."}/.*${*}"; done; }
arcege · 453 weeks and 2 days ago
thanks for your comment arcege but your modifications are not efficients. for example: sepath ^ps will not work with your hack. however, you right, i should not sort the PATH. Mobidyc
mobidyc · 453 weeks and 1 day ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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