sed -n '/^function h\(\)/,/^}/p'

Extract a bash function

I often need to extract a function from a bash script and this command will do it.
Sample Output
$ sed -n '/^function h\(\)/,/^}/p' .bash_profile
function h() {
    if [ -z "$1" ]
        history | grep "$@"

By: haivu
2009-10-19 07:55:35

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    col() { awk '{print $('$(echo $* | sed -e s/-/NF-/g -e 's/ /),$(/g')')}'; }
    tekniq · 2014-06-05 18:01:31 0
  • Had trouble with the other function, because of missing semicolons. (According to my bash on OS X)

    function cdf () { [ -f $1 ] && { cd $(dirname $1); } || { cd $1 ; }; pwd; };
    Josso · 2012-09-08 10:50:58 1
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    atb() { l=$(tar tf $1); if [ $(echo "$l" | wc -l) -eq $(echo "$l" | grep $(echo "$l" | head -n1) | wc -l) ]; then tar xf $1; else mkdir ${1%.tar.gz} && tar xf $1 -C ${1%.tar.gz}; fi ;}
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    relay · 2009-09-03 18:58:13 0
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    joedhon · 2014-02-09 12:19:29 0
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    snipertyler · 2013-08-08 06:44:29 0

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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