Linux zsh one-liner to Determine which processes are using the most swap space currently

for i in $(ps -ef | awk '{print $2}') ; { swp=$( awk '/Swap/{sum+=$2} END {print sum}' /proc/$i/smaps ); if [[ -n $swp && 0 != $swp ]] ; then echo -n "\n $swp $i "; cat /proc/$i/cmdline ; fi; } | sort -nr
Col 1 is swapped sum in kb Col 2 is pid of process Col 3 is command that was issued
Sample Output
 4428 9187 python/usr/share/system-config-printer/
 2012 9163 gnome-panel
 1516 9127 /usr/lib/gnome-settings-daemon/gnome-settings-daemon
 1408 18899 /usr/lib/gvfs/gvfsd-smb--spawner:1.9/org/gtk/gvfs/exec_spaw/4
 1040 1681 gnome-terminal

By: cbrinker
2010-01-22 00:09:46

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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