Rename all the files in the current directory into their sha1sum

find . -maxdepth 1 -type f| xargs sha1sum | sed 's/^\(\w*\)\s*\(.*\)/\2 \1/' | while read LINE; do mv $LINE; done

By: foremire
2010-01-25 20:21:01

What Others Think

can't see myself ever using this one ;) but you get a *star* for effort!
linuxrawkstar · 641 weeks and 6 days ago
That doesn't work if there are spaces in the filenames. This does it in 59 chars, not 113 (spaces are OK, but I don't check for dirs): for i in *; do mv "$i" $(sha1sum "$i" | cut -d\ -f1); done
flatcap · 641 weeks and 6 days ago
This is a bit simpler if you're just doing files in the current working directory. for i in *;do mv "$i" $(sha1sum "$i" | cut -d" " -f1);done
eightmillion · 641 weeks and 6 days ago
Actually, my version needs a directory check: for i in *;do [ -f "$i" ] && mv "$i" $(sha1sum "$i"|cut -d" " -f1);done
eightmillion · 641 weeks and 6 days ago
60 chars, but more beautiful: eval $(sha1sum * | sed 's/^\(\w*\)\s*\(.*\)/mv "\2" "\1";/')
flatcap · 641 weeks and 6 days ago
Hmm, your sed expression is flawed. It breaks on files with leading spaces (unlikely, I know). Change the middle from "\s*" to " " (space space).
flatcap · 641 weeks and 6 days ago
Thanks all, I'm new to sed, so the regex looks awkward.
foremire · 641 weeks and 5 days ago
Some of them do not work if you have a file called: '12" record'
unixmonkey8046 · 641 weeks and 2 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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