Converts reserved characters in a URI to their percent encoded counterparts.
Alternate python version:
echo "$url" | python -c 'import sys,urllib;print urllib.quote(sys.stdin.read().strip())'
Show Sample Output
Returns URL Encoded string from input ($1).
It only encodes non-Basic-ASCII chars, as they are the only ones not well readed by UTF-8 and ISO-8859-1 (latin-1). It converts all * C3 X (some latin symbols like ASCII-extended ones) and * C2 X (some punctuation symbols like inverted exclamation) ...UTF-8 double byte symbols to escaped form that every parser understands to form the URLs. I didn't encode spaces and the rest of basic punctuation, but supposedly, space and others are coded as \x20, for example, in UTF-8, latin-1 and Windows-cp1252.... so its read perfectly. Please feel free to correct, the application to which I designe that function works as expected with my assumption. Note: I specify a w=999, I didn't find a flag to put unlimited value. I just suppose very improbable surpass the de-facto 255 (* 3 byte max) = 765 bytes length of URL Show Sample Output
Similar to the perl version. Show Sample Output
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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uri_escape(){ local y;y="$@";echo -n ${y/\\/\\\\} | while read -n1;do [[ $REPLY =~ [A-Za-z] ]] && printf "$REPLY" || printf "%%%x" \'"$REPLY";done;echo;}
It's also quite a bit quicker. You're version also seems to be missing some semicolons. And when you use read with a variable specified, when it hits a space it sets that variable to null, causing printf to output "%0"s instead of "%20"s. You can avoid that, like I've done, by not supplying a variable to the read builtin.uri_escape(){ local y=$@:s/\\/\\\\/; for i in `seq 1 ${#y}`; do [[ "${y[i]}" =~ '[a-zA-Z0-9/.:?&=]' ]] && echo -n ${y[i]} || printf %%%x \'${y[i]}; done }