shell function to underline a given string.
grep xxxx *.csv
This would print the name of each csv file before each matching line, but the output would be hard to parse visually.
for i in *.csv; do printf "\n"; underline $i; grep "xxxx" $i; done
Will break the output into sections separated by the name of the file, underlined.
$ underline 'Underline me!' Underline me! ============= $ underline 'Underline me with dashes!' '-' Underline me with dashes! -------------------------
What do you think?
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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underline() { echo $1; echo "${1//?/${2:-=}}";}orunderline() { echo -e "$1\n${1//?/${2:-=}}";}underline() { printf "$1\n${1//?/${2:-=}}";}but this doesn't put a newline after the underline... ah. I see... that's 'echo -e' which interprets '\n' not 'echo -n' which removes the trailing new line. Thus I could useunderline() { printf "$1\n${1//?/${2:-=}}\n";}but I'd be a stroke over par.underline() { echo -e "\E[4m$1\E[0m" }you can colour it too then...