leapyear() { if [ $[$1 % 4] -eq 0 ] && [ $[$1 % 100] -ne 0 ] || [ $[$1 % 400] -eq 0 ]; then echo $1' is a leap year!'; else echo $1' is not a leap year.'; fi; }

Leap year calculation

Tested on bash, and follows all the rules about leap years.
Sample Output
$ leapyear 2000
2000 is a leap year!
$ leapyear 2400
2400 is a leap year!
$ leapyear 2600
2600 is not a leap year.

-2
By: kaedenn
2010-03-30 17:19:20

2 Alternatives + Submit Alt

What Others Think

leapyear() { [ $(date -d "Dec 31, $1" +%j) == 366 ] && echo leap || echo not leap; }
taliver · 425 weeks and 2 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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