Bash function to see if the day ends in "y"

function ends_in_y() { if [ `date +%A | sed -e 's/\(^.*\)\(.$\)/\2/'` == "y" ]; then echo 1; else echo 0; fi }
For those days when you need to know if something is happening because the day ends in "y".
Sample Output
$ ends_in_y
1

-3
2010-04-06 20:14:34

2 Alternatives + Submit Alt

What Others Think

Silly as it is, there are shorter ways to get there. You don't need the "-e", or the first () in sed. sed 's/^.*\(.$\)/\1/' But I prefer grep: function ends_in_y() { date +%A | grep -qv "y$"; echo $?; }
flatcap · 476 weeks ago
true
penpen · 476 weeks ago
And now for the ultimate solution: :
penpen · 476 weeks ago
for future reference, if you're grabbing some regular expression out of a line of text and discarding the rest (in this case, ".$") grep -o works wonders
camocrazed · 462 weeks ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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