Shows users and 'virtual users' on your a unix-type system

sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -u
Most systems (at least my macbook) have system users defined, such as _www and using "users" for example will not list them. This command allows you to see who the 'virtual' users are on your system.
Sample Output
USER
_mdnsresponder
_mysql
_postfix
_spotlight
_usbmuxd
_windowserver
_www
couchdb
daemon
lloyd
root

-4
By: binaryten
2010-07-07 08:20:28

3 Alternatives + Submit Alt

What Others Think

Interesting. What is this supposed to do? sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -u a b c d e h i j l m n o O p r s t u v
OJM · 435 weeks and 5 days ago
I think you need to put TWO spaces in sed pattern (maybe you do, but it's hard to see). When I do that, I get something like this: sudo lsof|sed 's/ */ /g'|cut -f3 -d' '|sort -u USER _coreaudiod _mdnsresponder _spotlight _usbmuxd _windowserver daemon george root
zabouti · 435 weeks and 5 days ago
I think tr -s instead of the sed: sudo lsof | tr -s ' ' | cut -f3 -d' ' | sort -u but I think ps can do this too. I'll post an alternative...
dfaulkner · 435 weeks and 5 days ago
If you want to collapse spaces in sed you should use the "one or more" repetition rather than "zero or more" sed 's/ \+/ /g' but what you're looking for, instead, is awk: sudo lsof | awk '{ print $3 }' | sort -u
Flameeyes · 435 weeks and 5 days ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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