list all file extensions in a directory

ls | perl -lne '++$x{lc $1} if /[.](.+)$/ }{ print for keys %x'
All with only one pipe. Should be much faster as well (sort is slow). Use find instead of ls for recursion or reliability. Edit: case insensitive
Sample Output
$ ls | perl -lne '++$x{lc $1} if /[.](.+)$/ }{ print for keys %x'
bash
py
txt
tar.gz

$ find . -maxdepth 1 -name "*.*" | perl -lne '++$x{lc $1} if /[.](.+)$/ }{ print for keys %x'
bash
py
txt
tar.gz

-3
2010-08-13 20:05:15

11 Alternatives + Submit Alt

What Others Think

It doesn't work well. First of all, it doesn't sort on my machine. Second of all, it doesn't show that . in front. Just take ls -Xp | grep -Eo "\.[^/]+$" | sort | uniq instead.
lkjoel · 401 weeks ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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