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dir="/bin"; man $(ls $dir |sed -n "$(echo $(( $RANDOM % $(ls $dir |wc -l | awk "{ print $1; }" ) + 1 )) )p")
Broaden your knowledge of the utilities available to you in no particular order whatsoever! Then use that knowledge to create more nifty one-liners that you can post here. =p Takes a random number modulo the number of files in $dir, prints the filename corresponding to that number, and passes it as an argument to man.

-2
2010-08-20 16:31:50

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What Others Think

It worked on my machine, once I changed the first "ls" to "command ls". (I have a .bashrc ls function which sets --classify, so '*' is appended to all executables.) How about: (cd /bin; set -- *; x=$((1+($RANDOM % $#))); man ${!x})
quintic · 409 weeks and 3 days ago

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Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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