j=0;while true; do let j=$j+1; for i in $(seq 0 20 100); do echo $i;sleep 1; done | dialog --gauge "Install part $j : `sed $(perl -e "print int rand(99999)")"q;d" /usr/share/dict/words`" 6 40;done

pretend to be busy in office to enjoy a cup of coffee

This will turn it in an infinite loop and also shows random words from a file, so it won't be the same each time and also not just a number.

15
By: houghi
2010-10-08 12:12:00

9 Alternatives + Submit Alt

What Others Think

Not really sure why you need sed and Perl here. You could make use of $RANDOM instead: sed -n $(( $RANDOM * 3 ))p /usr/share/dict/words I multiplied by 3 since the limit of that variable is 32k. It would also be easy to do the whole radom-word-choice operation in a Perl one-liner.
dbbolton · 327 weeks and 1 day ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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