get function's source

typeset -f <function name>; declare -f <function name>
no need to reinvent the wheel. Thanks to the OP for the "obsolete" hint. 'declare' may come in pretty handy on systems paranoid about "up-to-dateness"
Sample Output
$ typeset -f startx
startx () 
    test -x /usr/bin/startx || { 
        echo "No startx installed" 1>&2;
        return 1
    /usr/bin/startx ${1+"$@"} 2>&1 | tee $HOME/.xsession-errors

By: unefunge
2010-11-24 15:59:42

1 Alternatives + Submit Alt

What Others Think

thx, but... help typeset typeset: typeset [-afFirtx] [-p] name[=value] ... Obsolete. See `declare'. declare -f startx
glaudiston · 565 weeks ago
anyway is better than the my one ;)
glaudiston · 565 weeks ago
Quite possible, I think there were some rumours about 'typeset' going obsolete -- 2005 or earlier. But it's still here ;-) Right now I'm using "GNU bash, version 4.1.7(1)-release (x86_64-suse-linux-gnu)" on OpenSUSE: no "obsolete" remarks in the manual.
unefunge · 565 weeks ago

What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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