Find most used focal lengths in a directory of photos

exiv2 *JPG | grep Focal | awk '{print $5}' | sort -n | uniq -c
First column is number of photos, second column is the focal length.
Sample Output
     17 17.0
      2 47.0
      1 50.0
      4 53.0
      6 78.0
      3 85.0

-1
By: ivanatora
2011-07-05 11:25:29

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What do you think?

Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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