sort lines by length

perl -C -e 'print for sort { length $a <=> length $b or $a cmp $b } <>' < /usr/share/dict/words | tail
making it "sound" more "natural" language like -- additionally sorting the longest words alphabetically: this approach is using: * to get at all lines of input * post-"for" structure * short-circuit-or in sort: if the lengths are the same, then sort alphabetically otherwise don't even evaluate the right hand side of the or * -C sets all input and ouput channels to utf8

3
By: dbr
2011-10-20 01:43:25

6 Alternatives + Submit Alt

What Others Think

perl -ne 'printf("%d\t%s", length, $_)'< /usr/share/dict/words | sort -n | tail | cut -f2
kev · 364 weeks and 6 days ago
this is not better just showing that schwartzian transform can be applied in perl one-liner.. perl -C -e 'print map { $_->[0] } sort { $a->[1] <=> $b->[1] } map { [$_,length $_] } <>' < /usr/share/dict/words | tail
alperyilmaz · 364 weeks and 1 day ago
the first approach was to show a more 'idiomatic' version to syssyphus' approach. the cool thing with schwartzian transforms is, you can plug more parts in, e.g. this equivalent (not efficient!): perl -C -e 'print map { $_->[0] } reverse grep { $got++ < 1_0 } reverse sort { $a->[1] <=> $b->[1] } map { [$_,length $_] } <>' < /usr/share/dict/words
dbr · 364 weeks and 1 day ago

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Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?

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